10^(-8)=x^2/(0.1-x)

Solution for 10^(-8)=x^2/(0.1-x) equation:

10^(-8)=x^2/(0.1-x)

We move all terms to the left:

10^(-8)-(x^2/(0.1-x))=0


Domain of the equation: (0.1-x))!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-0.1

x!=-0.1/1

x!=-0.1

x∈R


We add all the numbers together, and all the variables

-(x^2/(-1x+0.1))+10^(-8)=0

We add all the numbers together, and all the variables

-(x^2/(-1x+0.1))-8+1.0E=0

We multiply all the terms by the denominator


-(x^2-8*(-1x+0.1))+(1.0E)*(-1x+0.1))=0


We calculate terms in parentheses: -(x^2-8*(-1x+0.1)), so:

x^2-8*(-1x+0.1)

We multiply parentheses

x^2+8x-0.8

Back to the equation:

-(x^2+8x-0.8)


We add all the numbers together, and all the variables

-(x^2+8x-0.8)+(2.71828182846)*(-1x+0.1))=0

We get rid of parentheses

-x^2-8x+(2.71828182846)*(-1x+0.1))+0.8=0

We add all the numbers together, and all the variables

-1x^2-8x+(2.71828182846)*(-1x+0.1))+0.8=0